Question 168961
(1) {{{3x + y = 5}}}
(2) {{{-2x + 3y = 4}}}
This is 2 equations with 2 unknowns, so it's solvable
Multiply (1) by {{{3}}} and subtract (2) from (1)
To subtract, change all the signs of (2) to minus
{{{9x + 3y = 15}}}
{{{-(-2x) - 3y = -4}}}
Now I'll rewrite these
{{{9x + 3y = 15}}}
{{{2x - 3y = -4}}}
The result is:
{{{11x  = 11}}}
{{{x = 1}}}
Substitute this result back in (1)
(1) {{{3x + y = 5}}}
(1) {{{3*1 + y = 5}}}
{{{y = 5 - 3}}}
{{{y = 2}}}
The solutions are x = 1 and y = 2