Question 23660
C = 0.009x^2 - 1.8x + 100
COMBINE X^2 AND X TERMS TO FIT A PERFECT SQUARE
C=0.1{0.09X^2-18X}+100
C=0.1{(0.3X)^2-2*(0.3X)*30+30^2-30^2}+100
C=0.1{(0.3X-30)^2}+100-90
C=0.1{(0.3X-30)^2}+10
HENC C WILL BE MINIMUM IF {(0.3X-30)^2}IS MINIMUM WHICH BEING PERFECT SQUARE WILL BE MINIMUM ZERO WHEN 0.3X=30...OR...X=30/0.3=300/3=100...THAT IS WHEN 100 BALLS ARE MADE PER HOUR....THE MINIMUM COST IS C=10...