Question 168865
Please solve {{{ 64 = 4^(2x) 16^(3x^2) }}}, it is 16 to the exponent of (3x^2)
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{{{ 64 = 4^(2x) 16^(3x^2) }}}
{{{ 2^6 = 2^(4x) * 2^(12x^2)}}}
{{{ 2^6 = 2^(4x + 12x^2)}}}
{{{12x^2 + 4x = 6}}}
{{{6x^2 + 2x - 3 = 0}}}
x = -1/6 + sqrt(19)/6
x = -1/6 - sqrt(19)/6