<PRE><B>Question 168896</B>
x^2/3x^2 - 5x - 2 minus 2x/3x + 1 times 1/x - 2
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= [x^2/(3x^2 -5x -2)] - [2x/(3x+1)]*[1/(x-2)]

= [x^2/(3x^2 -6x+x -2)] - [2x/[(3x+1)(x-2)]]

= [x^2/3x(x-2) + (x-2)] - [2x/[(3x+1)(x-2)]]

= [x^2/(x-2)(3x+1)] - [2x/[(3x+1)(x-2)]]

= [x^2 - 2x]/[(3x+1)(x-2)]]

= [x(x-2)]/[(3x+1)(x-2)]]

= x/(3x+1)

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Cheers,
Stan H.</PRE>