Question 2689
Let the points be P(7,-2) and Q(5,1).
<br>
Slope of a line (m) =
= (difference of ordinates)/(difference of abcissae)
= (y2-y1)/(x2-x1)
= (1-(-2))/(5-7)
= (1+2)/(2)
= (3/2)
<br>
Now m=3/2
<br>
Taking form of:
y-y1=m(x-x1)
<br>
y-(-2)=3/2(x-7)
y+2=3/2(x-7)
2y+4=3(x-7)
2y+4=3x-21
2y-3x=-21-4
2y-3x=-25
<br>
Converting to standard form of slope-intercept we get,
2y=3x-25

Here,slope(m)=(3/2)
     yintercept=(-25/2)
<P>
Hope this helps,
best of luck