Question 168836
lets call the numbers a,b,and c

a+b+c=105....eq 1
c=10b-11.....eq 2
2a=3b+7......eq 3
:
lets solve for a in eq 3.  a=(3b+7)/2
:
now lets take c's value from eq 2 and a's value from eq 3 and plug them into eq 1
:
((3b+7)/2)+b+(10b-11)=105  multiply all terms by 2
:
3b+7+2b+20b-22=210---> now combine like terms
:
25b=225:
{{{highlight(b=9)}}}
{{{highlight(c=10(9)-11=79)}}}
{{{highlight(a=(3(9)+7)/2=17)}}}
a,b,c........17,9,79 respectively