Question 168829
find 4 consecutive intergers such that the sum of the first three exceeds the 4th by 18. I can not figure out how to write out the problem to solve it. 
x+x+2+x+4=x+6-18 
is that correct
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It says integers, not even integers. And, the sum exceeds the 4th, so add 18 to the 4th, not subtract.
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So x + x+1 + x+2 = x+3 + 18
3x+3 = x+21
2x = 18
x = 9 (the 1st)
Check:
9+10+11 = 30
12 + 18 = 30