Question 168831
{{{y+3=-3(x-6)}}} Start with the given equation



{{{y+3=-3x+(-3)(-6)}}} Distribute



{{{y+3=-3x+18}}} Multiply {{{-3}}} and {{{-6}}} to get {{{18}}}



{{{y=-3x+18-3}}} Subtract 3 from  both sides to isolate y



{{{y=-3x+15}}} Combine like terms {{{18}}} and {{{-3}}} to get {{{15}}} 



Now the equation is in slope-intercept form {{{y=mx+b}}} where the slope is {{{m=-3}}} and the y-intercept is {{{b=15}}} note: the y-intercept is the point (0,15)