Question 168747
{{{sqrt(28a^2)/sqrt(7)=sqrt((28a^2)/(7))=sqrt(4a^2)=sqrt(2^2a^2)=sqrt(2^2)sqrt(a^2)=2a}}}



So {{{sqrt(28a^2)/sqrt(7)=2a}}} where {{{a>=0}}}



Notes:



1) Every variable is positive. So this means that {{{a>=0}}}



3) {{{sqrt(A)/sqrt(B)=sqrt(A/B)}}}



2) {{{sqrt(x^2)=x}}} where {{{x>=0}}}