Question 168655
lets call our consecutive even integers: x, x+2, x+4, x+6

(x+6)=1/2(x+(x+2)+(x+4))+2------multiply all terms by 2

2x+12=x+x+2+x+4+4
:
2x+12=3x+10
:
{{{highlight(x=2)}}} so integers are 2,4,6,and 8