Question 168568
a three-digit number, which is divisible by 10, has a hundreds digit that is ove less than its tens digit. the number also is 52 times the sum of its digits. find the number
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Since it is divisible by 10 let the number be 100a + 10b 
a = b - 1
100a + 10b = 52(a+b) 
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Use substitution to bolve for "b".
100(b-1) + 10b = 52(b-1+b)
100b - 100 + 10b = 104b - 52
6b = 48
b = 8
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solve for "a":
a = 8-1 = 7
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The number is 100*7 + 8*10 = 780
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Cheers,
Stan H.