Question 168522
 I've checked all over this site, but can't find a response for these 2 problems.
Please help! 
1.Find the coordinates of the point C, halfway between the points A(5,1) and B(-2,7).
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The easiest way to do these is to find the average of x and y separately.
A(5,1) and B(-2,7).
For x: (5 + (-2))/2 = 3/2
For y: (1+7)/2 = 4
So the point is (3/2,4) or (1.5,4)
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2. What is the equation of the perpendicular bisector of teh line between the points (2,2) and (6,6)? 
The mid-point is found in the same way as above, and is (4,4).
The slope of the line is the (diff in y)/(diff in x) = 1
The slope, m, of a line perpendicular is the negative inverse, = -1.
Then,
y-y1 = m*(x-x1) where (x1,y1) is the point (4,4)
y-4 = -1(x-4)
y-4 = -x + 4
x+y = 8