Question 168513
y=1/2x+1 
y=[x+2]-3

{{{drawing(300,300,-7,8,-8,10,graph(300,300,-7,8,-8,10,abs(x+2)-3,(1/2)x+1))}}}----> RED LINE >>> {{{y=abs(x+2)-3}}}, GREEN LINE >>> {{{y=(1/2)x+1}}}
.
Thank you,
Jojo