Question 168503
a = largest angle
b = second largest angle
c = smallest angle
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a = 2*b
(1/3)*a = b - c + 10
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c formula becomes:
c = b - (1/3)*a + 10
which becomes:
c = b - (2/3)*b + 10
which becomes
c = (1/3)*b + 10
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a + b + c = 180 (sum of angles of a triangle = 180)
2*b + b + (1/3)*b + 10 = 180
2*b + b + (1/3)*b = 170
3*b + (1/3)*b = 170
multiply both sides by 3:
9*b + b = 510
10*b = 510
b = 51
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2*b = 102 = a
c = b - (1/3)*a + 10
c = 51 - (1/3)*102 + 10
c = 27 
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a = 102
b = 51
c = 27
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a + b + c = 180
102 + 51 + 27 = 180
180 = 180
ok
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a = 2 * b
102 = 2 * 51
102 = 102
ok
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(1/3)*a = (b-c) + 10
1/3)*102 = (51 - 27) + 10
34 = 30
ok
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