Question 168481
You can factor out 2z^2 from each term and you are left with {{{2z^2(15z^6+22z^3+8)}}}
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*If you have trouble finding out if anything else will factor you can write out a factor tree for each term.  {{{(3*z*z*z*z*z*z)+(2*11*z*z*z)+(2*2*2)}}}
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Because there are no common terms to all of the terms then there is nothing left to factor.
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I hope this helps!
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