Question 168391
Instead of:
(y-(2/y+1))/(1-(2/y+1))
.
I think you mean this:
{{{(y-(2/(y+1)))/(1-(2/(y+1)))}}}
Multiply by (y+1)/(y+1): 
{{{(y-(2/(y+1)))(y+1)/(1-(2/(y+1)))(y+1) }}}
{{{(y(y+1)-2)/((y+1)-2) }}}
{{{(y^2+y-2)/(y+1-2) }}}
{{{(y^2+y-2)/(y-1) }}}
factoring the numerator:
{{{(y+2)(y-1)/(y-1) }}}
canceling like-terms:
{{{y+2 }}}