Question 23665
Is this the correct problem: {{{((6x^2)/(8x))*( (-4x^3)/(2x^2))}}}?


If so, multiply numerator times numerator and denominator times denominator:
{{{(-24x^5)/(16x^3)}}}


This fraction reduces by dividing out an 8 factor and also {{{x^3}}}.  When you divide variables with the same base number, remember that you SUBTRACT exponents.

{{{(-24x^5)/(16x^3)}}}
{{{-3x^2/2)}}}


R^2 at SCC