Question 168362
The problem says {{{l = w}}}
If I call the height {{{h}}}, then the
volume will be {{{V = l*w*h}}} and since {{{l = w}}}
{{{V = w^2*h}}}
It is given that {{{V = 121}}} in3
{{{121 = w^2*h}}}
The length of the tape measures 20 inches, 
which is 1 inch more than the shortest 
distance around the box.
So, the distance around the box is {{{19}}}in
The box has a square base with sides = {{{w}}}
so the distance around the bnox = {{{4w}}}
{{{4w = 19}}}
{{{w = 19/4}}}
{{{121 = w^2*h}}}
{{{121 = (19/4)^2*h}}}
Now solve for {{{h}}}
{{{h = 121 / (361/16)}}}
Now find {{{h}}} and solve for {{{V}}}
Hope I got it right- I think so