Question 168354
lets call x the side of the small field so other 2 fields will have sides of 
x+1 and x+3.  total of all these areas will equal 38
:
{{{x^2+(x+1)^2+(x+3)^2=38}}} multiply this out and end up with
:
{{{3x^2+8x-28=0}}} solve by quadratic formula
and you end up with 1 postive answer of 2
:
so areas of the fields are 4,9,25  which equals 38 in total
:

*[invoke quadratic "x", 3, 8, -28]