Question 23678
I'm assuming that you are NOT replacing the first card and then drawing the second.  For the first card drawn , probability of ace is 4/52.  Then for the second card, after the first ace is drawn, there are only 3 aces left out of 51 cards, so probability is 3/51.  The probability of performing two independent activities such as this is actually the product of the probabilities:  {{{(4/52)*(3/51)}}}.  This reduces to {{{(1/13)*(1/17) = 1/221}}}.


R^2 at SCC