Question 168341
The monthly revenue for this
model is given by the formula
R(p)= -0.08p2 + 300p.
Revenue is the product of the price p and the demand
(quantity sold).
a) Factor out the price on the right-hand side of the
formula.
R(p) = p(-0.08p + 300)
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b) Write a formula D(p) for the monthly demand.
D(p) = -0.08p + 300
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c) Find D(3000).
D(3000) = -0.08(3000)+300 = 60
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d) Use the accompanying graph to estimate the price at
which the revenue is maximized. Approximately how
many pools will be sold monthly at this price?
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No graph was provided.
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Cheers,
Stan H.