<PRE><B>Question 168326</B>
{1/x^2-36}-{x+3/x^2-7x+6} 

= [1/(x-6)(x+6)] - [(x+3)/(x-3)(x-2)]

lcd = (x-6)(x+6)(x-3)(x-2)

Rewrite each fraction with lcd as its denominator:

= [(x-3)(x-2]/lcd - [(x+3)(x+6)(x-6)]/lcd

Combine the numerators over the lcd:

= [x^2-5x+6-(x+3)(x^2-36)]/lcd

= [x^2-5x+6-x^3-36x+3x^2-108]/lcd

= [-x^3+4x^2-41x-102]/lcd
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Cheers,
Stan H.

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