Question 168259
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Consecutive Even Integers --->{{{system(x=1stEven,x+2=2ndEven,168=product)}}}
Continuing,
{{{(x)(x+2)=168}}},EQN 1:
Expand & Transpose
{{{x^2+2x-168=0}}}, factor out, perfect square
{{{(x+14)(x-12)=0}}}
2 values ----->{{{system(x=-14,highlight(x=12))}}}
Therefore:
{{{x=12}}}, 1st even number
{{{12+2=highlight(14)}}}, 2nd even number
Check Via EQN 1:
{{{12*14=168}}}
{{{168=168}}}
Thank you,
Jojo</pre>