Question 168287
3a/a+1+2a/a-3 ----> {{{(3a/(a+1))+(2a/(a-3))}}}, right?
Then,
{{{(3a(a-3)+2a(a+1))/(a+1)(a-3)}}}
Expand,
{{{(3a^2-9a+2a^2+2a)/(a+1)(a-3)}}}
{{{(5a^2-7a)/(a+1)(a-3)}}}
{{{a(5a-7)/(a+1)(a-3)}}}
Thank you,
Jojo