Question 168280
Since {{{t}}} varies inversely to {{{r}}}, it follows:
{{{t[1]r[1]=t[2]r[2]}}}
where----{{{system(t[1]=5hrs,t[2]=t[2],r[1]=55mph,r[2]=40mph)}}}
Continuing,
{{{5*55=t[2]*40}}}
{{{275/40=t[2]cross(40)/cross(40)}}}
{{{highlight(t[2]=6.875hrs)}}} ---> 6 hrs & 52.5 mins
*It make sense for {{{t}}} to go up, since {{{r}}} goes down,Varies Inversely.
Thank you,
Jojo