Question 168268
Please solve the problem. The product of two consecutive integers is 5 more than their sum. Find the integers.
.
Let x = first consecutive integer
then
x+1 = second consecutive integer
.
x(x+1) = 5 + x + x+1
x^2+x = 6 + 2x
x^2-x-6 = 0
(x-3)(x+2) = 0
x = {-2, 3}
.
Two possible solutions:
-2 and -1
3 and 4