Question 168265
The x-intercepts are found by setting y equal to zero and solving for 'x'.
y = x^2 + 4x - 45
0 = x^2 + 4x - 45
0 = (x+9)(x-5)
x = {-9, 5}
.
So, the x-intercepts are at (-9,0) and (5,0)