Question 168139
lets call one travelers rate r and the other r+20. time is the same and lets call the distances x and 125-x

r(5/4)=x.........eq 1
(r+20)(5/4)=125-x..eq 2

lets use x's value from 1st equation and plug it into the 2nd eq

r+20(5/4)=125-(5/4)r

multiply both sides by 4

5r+100=500-5r

10r=400

{{{highlight(r=40)}}}speed of the slower traveler

{{{highlight(r+20=60)}}}speed of the faster traveler