Question 168070
{{{10x^2=9x+9}}}, EQN 1
{{{10x^2-9x-9=0}}} -------> it follows quadratic eqn: {{{ax^2+bx+c=0}}}
where---->{{{system(a=10,b=-9,c=-9)}}}
Plug in the values to quadratic eqn:
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}
ANSWERS:
{{{highlight(x=3/2)}}};{{{highlight(x=-3/5)}}}
Check via EQN 1;
{{{10(3/2)^2=9(3/2)+9}}}
{{{10(9/4)=(27/2)+9}}}
{{{90/4=(27+18)/2}}}
{{{45/2=45/2}}}
Thank you,
Jojo