Question 167314
Both are Line Equations---{{{system(x-2y=-6,y=-3x/2-1)}}}
It seems you want them to show in the graph.
In the 1st eqn, as we follow Slope-Intercept Form,
{{{2y=x+6}}} --->{{{cross(2)y/cross(2)=(x+6)/2}}}
{{{y=(1/2)x+(6/2)}}} 
Reduced -->{{{y=(1/2)x+3}}}, {{{Slope=1/2}}}, y-intercept=3
f(y)=0:
{{{(1/2)x=-3}}} ---->{{{cross(1/2)x/cross(1/2)=-3/(1/2)}}}
{{{x=-3(2/1)=-6}}}
.
2nd eqn:
{{{y=-3x/2-1}}} ---> already in the format: {{{Slope=-3/2}}}, y-intercept=-1
F(y)=0:
{{{(-3/2)x=1}}} ----> {{{cross(-3/2)x/cross(-3/2)=1/(-3/2)}}}
{{{x=-2/3}}}
As we see below,
{{{drawing(300,300,-7,7,-4,7,grid(1),graph(300,300,-7,7,-4,7,(1/2)x+3,(-3/2)x-1),circle(-6,0,.15),circle(0,3,.15),circle(-2/3,0,.15),circle(0,-1,.15))}}} ---> RED Line >>>> {{{x-2y=-6}}}; GREEN Line>>>>> {{{y=(-3/2)x-1}}}
Thank you,
Jojo