Question 168043
sooo...we're now in calculus.com...


r=h/2  __  V=π(r^2)h/3  __  substituting __ V=π(h^3)/12


differentiating __ dV/dT=(π/12)(3h^2)dh/dT __ dh/dT=(dV/dT)/[(π/12)(3h^2)]


dh/dT=8/(π/4)(6^2)=32/(36π)=.283ft/min (approx)