Question 168028
Factor completely by grouping 
27x^2 - 117x - 90

= 9(3x^2 - 13x - 10)

= 9(3x^2 - 15x + 2x - 10)

= 9(3x(x-5)+2(x-5))

= 9(x-5)(3x+2)

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Cheers,
Stan H.