Question 2736
{{{x^2+2x-6=3}}}
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{{{x^2+2x-6-3=0}}}
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{{{x^2+2x-9=0}}}
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Compare to ax^2+bx+c=0
We get:
a=1
b=2
c=-9
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Using the formula,
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
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{{{x = (-2 +- sqrt( 2^2-4*1*-9 ))/(2*1) }}} 
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{{{x = (-2 +- sqrt( 4+36 ))/(2) }}} 
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Root of 40 = 6.3245 = 6.325
Now value of x will be,
x=(-2+6.325)/2 AND (-2-6.325)/2
x=2.1625 AND -0.1754
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<B>Solution set={2.163,-0.175}</b>
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Hope this helps,
Best of luck.