Question 167970
{{{log(x,(1/64))=-3}}} Start with the given equation



{{{log(x,(1/4^3))=-3}}} Rewrite {{{64}}} as {{{4^3}}}



{{{log(x,(4^(-3)))=-3}}} Rewrite  {{{1/4^3}}} as {{{4^(-3)}}}
 


{{{x^(-3)=4^(-3)}}} Rewrite the equation using the property: {{{log(b,(x))=y}}} ====> {{{b^y=x}}}



Since the exponents are equal, this means that the bases are equal. So this means that {{{x=4}}}



So the solution is {{{x=4}}}