<PRE><B>Question 167925</B>
     3 times the first of three consecutive numbers is 4 more than 2 times the second.
.
Let x = 1st of 3 consecutive numbers
then
x+1 = 2nd of 3 consecutive numbers
x+2 = 3rd of 3 consecutive numbers
.
3x = 2(x+1) + 4
3x = 2x + 2 + 4
3x = 2x + 6
x = 6 (first number)
.
second number:
x+1 = 6+1 = 7
third number:
x+2 = 6+2 = 8
.
The numbers: 6,7,8
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