Question 167833
Use the fact that:
{{{Log[b](x) = y}}} means {{{x = b^y}}}
{{{Log[6](4x+1) = 2}}} means {{{(4x+1) = 6^2}}} so...
{{{4x+1 = 36}}} Subtract 1 from both sides.
{{{4x = 35}}} Divide both sides by 4.
{{{x = 8.75}}}