Question 167834
8x-4y=-76_5x+2y=-16

Multiply each equation by the value that makes the coefficients of y equal.  This value is found by dividing the least common multiple of the coefficients of y by the current coefficient.  In this case, the least common multiple is 4.
8x-4y=-76_2*(5x+2y=-16)

Multiply each equation by the value that makes the coefficients of y equal.  This value is found by dividing the least common multiple of the coefficients of y by the current coefficient.  In this case, the least common multiple is 4.
8x-4y=-76_2*(5x+2y)=2(-16)

Multiply 2 by each term inside the parentheses.
_2*(5x+2y)=-32

Multiply 2 by each term inside the parentheses.
_(10x+4y)=-32

Remove the parentheses around the expression 10x+4y.
_10x+4y=-32

Add the two equations together to eliminate y from the system.
10x+4y=-32_<U> 8x-4y=-76<u>_18x   =-108

Divide each term in the equation by 18.
x=-6

Substitute the value found for x into the original equation to solve for y.
8(-6)-4y=-76

Multiply 8 by each term inside the parentheses.
-48-4y=-76

Move all terms not containing y to the right-hand side of the equation.
-4y=-28

Divide each term in the equation by -4.
y=7

This is the final solution to the independent system of equations.
x=-6
y=7