Question 167786

{{{(x+3)^2=49}}} Start with the given equation.



{{{x+3=0+-sqrt(49)}}} Take the square root of both sides.



{{{x+3=sqrt(49)}}} or {{{x+3=-sqrt(49)}}} Break up the "plus/minus" to form two equations.



{{{x+3=7}}} or {{{x+3=-7}}}  Take the square root of {{{49}}} to get {{{7}}}.



{{{x=-3+7}}} or {{{x=-3-7}}} Subtract {{{3}}} from both sides.



{{{x=4}}} or {{{x=-10}}} Combine like terms.



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Answer:



So the solutions are {{{x=4}}} or {{{x=-10}}}.