Question 167780
Can you please help me solve this? This is what I have so far. 
log5(x+3)+log5(x-3)=3
log5{(x+3)(x-3)}=3
(x+3)(x-3)=3^5   It's the base to the exponent.
x^2-9=243 
How do I finish this? 
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log5(x+3)+log5(x-3)=3 I assume this is where you started.
Raise 5 to the power of each term.  The 2 terms added are multiplied, since the logs are added.
(x-3)*(x+3) = 5^3 = 125
x^2-9 = 125
x^2 = 134
x = ± sqrt(134) = apx ± 11.576