Question 167737
A partial solution set is given. Find the complete solution set. 
x^5+4x^4+4x^3-x^2-4x-4=0;{1,-2,-2}
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Using synthetic division you get:
1)....1....4....4....-1....-4....-4
.......1....5....9.....8.....4...|..0

-2)....1....3....3....2...|..0

-2)....1....1....1...|..0

Quotient: x^2 + x + 1

Solve with quadratic equation:
x = [1 +- sqrt(1-4*1*1)]/2

x = (1+isqrt(3))/2 or x = (1-isqrt(3))/2
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Cheers,
Stan H.