Question 167721

{{{(x^2+3x-10)/(x^2+x-20)}}} Start with the given expression.



{{{((x+5)(x-2))/(x^2+x-20)}}} Factor {{{x^2+3x-10}}} to get {{{(x+5)(x-2)}}}.



{{{((x+5)(x-2))/((x+5)(x-4))}}} Factor {{{x^2+x-20}}} to get {{{(x+5)(x-4)}}}.



{{{(highlight((x+5))(x-2))/(highlight((x+5))(x-4))}}} Highlight the common terms. 



{{{(cross((x+5))(x-2))/(cross((x+5))(x-4))}}} Cancel out the common terms. 



{{{(x-2)/(x-4)}}} Simplify. 



So {{{(x^2+3x-10)/(x^2+x-20)}}} simplifies to {{{(x-2)/(x-4)}}}.



In other words, {{{(x^2+3x-10)/(x^2+x-20)=(x-2)/(x-4)}}} where {{{x<>-5}}} or {{{x<>4}}}