Question 167656
let the angles of the triangle be k, m, and r.
let k = 2*m
let k = c-r
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if k = 2*m, then m = k/2
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if k = r-5, then r = k+5
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since the sum of the interior angles of a triangle = 180 degrees, then
k + m + r = 180
substituting k/2 for m, and k+5 for r, we get:
k + k/2 + k + 5 = 180
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combining like terms, we get:
2*k + k/2 + 5 = 180
subtracting 5 from both side of the equation we get:
2*k + k/2 = 175
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since 2*k is the same as 4*k/2, we can substitute to get:
4*k/2 + k/2 = 175
since the denominators on the left hand side of the equation are the same, this equation becomes:
(4*k + k)/2 = 175
which becomes:
(5*k)/2 = 175
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multiplying both sides of the equation by 2 gets:
5*k = 350
dividing both sides of the equation by 5 gets:
k = 70
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k = 70
m = k/2 = 35
r = k+5 = 75
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70 + 35 + 75 = 180
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algebraic expression to solve the problem was derived above.
it started off as
k+m+r = 180
we solved for m in terms of k.
we solved for r in terms of k.
equation became:
k + (k/2) + (k+5) = 180
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the rest was simplification to come up with k = 70.
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