Question 167638
A box contains 42 batteries, 7 of which are defective. If 5 are selected at random, find the probability that: all are defective and none are defective.
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P(all are defective) = 7C5/42C5 = 21/850668 = 0.000024685....
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P(none are defective) = 35C5/42C5 = 324632/850668 = 0.38162...
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Cheers,
Stan H.