<PRE><B>Question 167594</B>
Question reads : X+1 over x+3 -(minus) x^2 over x^2 + 4x + 3
----------------
[(x+1)/(x+3)] - [x^2/(x^2+4x+3)]

= [(x+1)/(x+3)] - [x^2/((x+3)(x+1))]

lcd = (x+3)(x+1)

Rewrite each fraction with the lcd as its denominator:

= (x+1)^2/lcd - x^2/lcd

Combine the numerators over the lcd

= [(x+1)^2 - x^2]/lcd

= [2x+1]/[(x+1)(x+3)]
==========================
Cheers,
Stan H.</PRE>