Question 167543
solve by elimination method:
0.3x-0.2y=4
0.4x+0.3y=73/19

eq 1:
3x-2y = 40

eq 2:
4x-3y = 730/19

from eq 1
x = (40+2y)/3

sub. in eq2,
4(40+2y)/3 -3y =730/19
(160+8y)/3 - 3y = 730/19
160+8y - 9y = 2190/19
y = 160-2190/19
   =3040-2190 /19
y    =850/19

x = 2460/57