Question 167530
    the sum of two integers is greater than 12, one integer is ten less than twice the other. what are the least values of the integers?
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Let x = one integer
and y = other integer
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x+y > 12
x = 2y-10
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2y-10 + y > 12
3y-10 > 12
3y > 22
y > 22/3 
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The smallest integer value of y is 8.
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to find x:
x = 2y-10
x = 2(8)-10
x = 16-10
x = 6
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The two integers: 6 and 8