Question 167495
Simplify:
{{{-(4w^(-3)*z^(-5))(8w)^2}}} Square the last factor {{{(8W)^2 = 64w^2}}}
{{{-(4w^(-3)*z^(-5))(64w^2)}}} Multiply the integers.{{{4*64 = 256}}}
{{{-(256w^(-3)*z^(-5))(w^2)}}} Multiply the w's by adding their exponents. {{{w^(-3)*w^2 = w^(-1)}}}
{{{-(256w^(-1)*z^(-5))}}} Simplify by putting the factors with negative exponents into the denominator thus making the exponents positive.
{{{-(256/(w*z^5))}}} or you can write this as: {{{(-256)/(wz^5)}}}