Question 167511
Due to melting, an ice sculpture loses one-half its weight every hour. After 8 hours, it weights 5/16 of a pound. How much did it weigh in the beginning?
;
Use the decay formula: A = Ao(2^(-t/h))
where 
Ao is initial amt (what we are solving for)
A = resulting amt (5/16)
t = time in hrs (8)
h = time required for substance to lose half it's weight (1hr)
:
Ao(2^(-8/1)) = .3125; (decimal value for 5/16)
;
Using a calc find 2^-8
Ao * .0039  = .3125
Ao = {{{.3125/.0039}}}
Ao = 80.1 ~ 80 lbs