Question 167498
The Yankee Clipper leaves the pier at 9:00am at 8 knots (nautical miles per hour).A half hour later,The Riverboat Rover leaves the same pier in the same direction traveling at 10 knots.
At what time will The Riverboat Rover overtake The Yankee Clipper? 
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The distances will be the same.
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Clipper DATA:
rate = 8 kts/hr ; time = x hrs ; distance = rt = 8x kts
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Rover DATA:
rate = 10 kts/hr ; time = (x-(1/2)) hrs ; distance = rt = 10(x-(1/2)) kts
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EQUATION:
8x = 10(x-(1/2))
8x = 10x - 5
2x = 5
x = 5/2 hrs 
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9:00 am + (5/2) hrs. = 11:30 am
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Cheers,
Stan H.