Question 167456
{{{a^2+b^2=c^2}}}-eq where we will call a the shortest leg, b the other leg,and c the hypothenuse.  Lets call b=b and c=b+1 where b and b+1 are two consecutive whole numbers. no substitute our known numbers and variables into the equation.

{{{29^2+b^2=(b+1)^2}}} solving we have {{{841+b^2=b^2+2b+1}}}

{{{2b=840}}} {{{highlight(b=420)}}}other leg  {{{highlight(c=420+1=421)}}} hypothenuse